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(4.9^2)x-15x+5=0
We add all the numbers together, and all the variables
-15x+(4.9^2)x+5=0
We multiply parentheses
4x^2-15x+5=0
a = 4; b = -15; c = +5;
Δ = b2-4ac
Δ = -152-4·4·5
Δ = 145
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-15)-\sqrt{145}}{2*4}=\frac{15-\sqrt{145}}{8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-15)+\sqrt{145}}{2*4}=\frac{15+\sqrt{145}}{8} $
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